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agabu38
02.07.2021 •
Mathematics
In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is
, where t is the time in seconds, and h is the height of the jump, in feet.
Player 1 had a hang time of 0.9 s. Player 2 had a hang time of 0.8 s. To the nearest inch, how much higher did Player 1 jump than Player 2?
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Ответ:
8 inches
Step-by-step explanation:
Given:
t = 2 ( 2h/32 ) ^1/2 ( or: t = 2 * sqrt ( 2h/32) ).
Step 1: First Player
0.9 = 2 * sqrt( 2h/32 ) / ^2 ( we will square both sides of equation )
0.81 = 4* 2h/32
0.81 = h/4
h 1 = 0.81 * 4 = 3.24 ft
Step 2: Second Player
0.8 = 2 * sqrt( 2h/32 ) /^2
0.64 = 4 * 2 h/32
h 2 = 0.64 * 4 = 2.56 ft
Step 3: Simplify
h 2 - h 1 = 3.24 - 2.56 = 0.68 ft
and since 12 in = 1 ft:
0.68 * 12 = 8.16 in ≈ 8 in.
Ответ:
The guy above me was correct. It is 8 inches!
Step-by-step explanation:
Ответ:
14
Step-by-step explanation:
(4*5)+(2*3)
20-6
14.