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marialion5278
13.10.2019 •
Mathematics
In δbcd, \overline{bd} bd is extended through point d to point e, m∠cde = (6x-13)^{\circ}(6x−13) ∘ , m∠bcd = (2x+10)^{\circ}(2x+10) ∘ , and m∠dbc = (x+1)^{\circ}(x+1) find m∠cde.
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Ответ:
m∠CDE = 35°
Step-by-step explanation:
The exterior angle CDE is equal to the sum of the opposite interior angles, BCD and DBC. So, you have ...
6x -13 = (2x+10) +(x +1)
3x -24 = 0 . . . . . . . . . . . . subtract the right side, simplify
x -8 = 0 . . . . . . . . . . . . . . divide by 3
x = 8 . . . . . . . . . . . . . . . . . add 8
6x -13 = 6·8 -13 = 35 . . . . substitute for x in the expression for CDE
The measure of angle CDE is 35°.
Ответ: