In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?

1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places =

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

56/112  or 29/56

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

We have 8 divided into a number as there are 8 participants.

so we can do; 8 x7 = 56 and expand 56 as the median after 4 weeks as 4 weeks is the total

We can divide 56 by 4 and express it must be greater than 8 but no greater than 56-3 = 53 week

Answer mean median and range per week is not conclusive,

Answer mean median per day is not conclusive,

Answer range per day could be shown 112-56=56

As days are 28 x 4 participants = 112 then we have a 50% conclusion to the mean and to the range.

56/112 tests