In ΔJKL, \overline{JL} JL is extended through point L to point M, \text{m}\angle JKL = (3x-16)^{\circ}m∠JKL=(3x−16) ∘ , \text{m}\angle LJK = (2x+15)^{\circ}m∠LJK=(2x+15) ∘ , and \text{m}\angle KLM = (8x-19)^{\circ}m∠KLM=(8x−19) ∘ . Find \text{m}\angle LJK.m∠LJK.

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