In justin's school 0.825 of the students participate in a sport. if there are 1000 students in justin's school, how many participate in a sport?

825 students

Step-by-step explanation:

When we say 0.825 students participate, we are actually meaning that 82.5% of the students are participating.

Note: to get decimal to percentage, we move the decimal 2 places right

In total there are 1000 students, so we need to find 82.5% of them to find the number who participate in a sport.

Note: To get this, we need to multiply 1000 by the DECIMAL of 82.5%, which is 0.825.

Hence, we have 1000 * 0.825 = 825 students

825

Step-by-step explanation:

Let the number of students who participated in the sport be x, which is equivalent to 0.825

The total number of students in the school is equivalent to 1

Expressing mathematically,we obtain

0.825:x=1:1000

By cross multiplying we obtain,

We finally simplify to arrive at

Hence the number of students who participated in the sport is 825

Step-by-step explanation:

Hello!

a)

The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.

To calculate the mean for data organized in this type of table you have to use the following formula:

X[bar]= (∑x'fi)/n

Where

x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2

fi represents the observed frequency for each class

n is the total of observations, you can calculate it as ∑fi

Class marks:

x₁'= (120+124)/2= 122

x₂'= (124+128)/2= 126

x₃'= (128+132)/2= 130

x₄'= (132+136)/2= 134

x₅'= (136+140)/2= 138

Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.

n= 7 + 8 + 13 + 9 + 3= 40

X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3

The estimated average height is 129.3cm

b)

This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.

The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a  mean value within the interval to calculate the mean of the sample.

I hope this helps!