mochoa4
07.06.2021 •
Mathematics
In ΔPQR, r = 9 inches, p = 6.6 inches and ∠Q=6°. Find the area of ΔPQR, to the nearest 10th of a square inch
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Ответ:
2.8 square inches
Step-by-step explanation:
Area of the triangle PQR = 1/2 rp sin <Q
Given
r = 9in
p = 6.6in
<Q =6°
Substitute into the formula;
Area of the triangle PQR = 1/2 * 9 * 6 sin6°
Area of the triangle PQR = 9 * 3 sin6°
Area of the triangle PQR = 27 sin6°
Area of the triangle PQR = 27(0.1045)
Area of the triangle PQR = 2.82
Hence the area to the nearest 10th of a square inch is 2.8 square inches
Ответ:
Step-by-step explanation:
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