In right triangle a efg m2 e= 25°. in right triangle a hjk, mz h=25º. which
similarity postulate or theorem proves that a efg and a hjk are similar?

Therefore the triangles are congruent by Angle Angle similarity postulate.

ΔEFG  ~ ΔHJK ...{ By Angle-Angle similarity postulate}

Step-by-step explanation:

Given:

In right triangle ΔEFG

m∠E= 25°.

In right triangle ΔHJK,

m∠H=25º

To Prove:

ΔEFG  ~ ΔHJK

Proof:

In right triangle ΔEFG  and ΔHJK

m∠ E ≅ m∠ H .......{measure of each angle is 25° given}

m∠ F ≅ m∠ J .........{Both triangle is Right angle Triangle therefore measure angle is 90° each}

∴ ΔEFG  ~ ΔHJK ...{ By Angle-Angle similarity postulate}

Therefore the triangles are congruent by Angle Angle similarity postulate.

ΔEFG  ~ ΔHJK ...{ By Angle-Angle similarity postulate}

Step-by-step explanation:

I'd tell her that if (and only if) her prediction is correct, the probability of getting tails is 0.5.  Actually, the probability of getting heads would be the same, 0.5.

In real life she would not necessarily get 240 tails out of 480 tosses, but the mean value of the number of tails would indeed be close to 0.5.