Mathematics: In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON

In the adjoining fig. In a circle with centre C

Ответ:

jm832098

26.08.2021

Mathematics

DC=CF

Diameter=20cmRadius=20/2=10cm

We know

$\boxed{\sf L=\dfrac{\theta}{180}\times πr}$

$\\ \large\sf\longmapsto L=\dfrac{90}{180}\times \dfrac{22}{7}\times 10$

$\\ \large\sf\longmapsto L=\dfrac{1}{2}\times \dfrac{220}{7}$

$\\ \large\sf\longmapsto L=\dfrac{110}{7}$

$\\ \large\sf\longmapsto L=15.5$

Now

$\\ \large\sf\longmapsto CF=L+r-DE$

$\\ \large\sf\longmapsto CF=15.7+10-16$

$\\ \large\sf\longmapsto CF=25.7-16$

$\\ \large\sf\longmapsto CF=9.7cm$

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Ответ:

necolewiggins3083

26.08.2021

Mathematics

$\large\sf\red{⟼L=18090×722×10}$

$\begin{gathered}\\ \large\sf\red{ ⟼ L=\dfrac{1}{2}\times \dfrac{220}{7}}\end{gathered}$

$\begin{gathered}{ \large\sf\red{⟼ L=\dfrac{110}{7}}\end{gathered}$

⟼ L=15.5

Now

⟼ CF=L+r−DE

⟼ CF=15.7+10−16

⟼ CF=25.7−16

⟼CF=9.7cm

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Ответ:

flore7488

12.11.2021

Mathematics

The probability is 1/9

Step-by-step explanation:

The inner square here is the smaller square

The area of a square is the square of its side length

The area of the small square is 4^2 = 16

The area of the big square is 12^2 = 144

The probability would be the area of the small square divided by that of the entire large square

We have this as;

16/144

= 1/9

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In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON

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In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON​

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In the adjoining fig. In a circle with centre C and chord DE ,ahe CF perpendicular to chord DE.If diameter of a circle is 20cm and DE=16cm,then CF=?GIVE REASON