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noeminm105
14.06.2021 •
Mathematics
In the circle shown below, The length of chord AB is 24 and the length of OC is 5. What is the radius of the circle with center O
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Ответ:
radius = 13
Step-by-step explanation:
OC is a perpendicular bisector of AB , then AC = 12
OA is the radius of the circle
Using Pythagoras' identity in right triangle OAC
OA² = OC² + AC²
OA² = 5² + 12² = 25 + 144 = 169 ( take the square root of both sides )
OA =
= 13
The radius = 13 units
Ответ:
13
Step-by-step explanation:
AB is bisected by perpendicular OC so AB is divided into intwo two equal halves.
if AB = 24
AC =![\frac{1}{2} *AB](/tpl/images/1373/6329/1edd8.png)
=![\frac{1}{2} *24](/tpl/images/1373/6329/31295.png)
=12
no join OA and name its length as x
OA = X
OC = 5
AC = 12
when u join O and A it forms a triangle . SO to find OA lets find pythagoras theorem
OC^2 + AC^2 = OA^2
5^2 + 12^2 = OA^2
25 + 144 = OA^2
169 = OA^2
13 = OA
radius is the line joining the centre and any point on the circumference.So here since O is the centre and A is the points on the circumference and they are joined so the line can be named as radius of a circle.
Therefore radius of a circle is 13
Ответ: