In the given figure lines XY and MN intersect
ato. If YOP-90° and a: b=2:3,
find

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Ответ:

unknownyobutt21

06.12.2021

Mathematics

0.9826

Step-by-step explanation:

Given : Mean : $\lambda =3\text{ calls per minute}$

For two minutes period the new mean would be :

$\lambda_1=2\times3=6\text{ calls per two minutes}$

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda_1}\lambda_1^x}{x!}$

Then ,the required probability is given by :-

$P(X\geq2)=1-(P(X\leq1))\\\\=1-(P(0)+P(1))\\\\=1-(\dfrac{e^{-6}6^0}{0!}+\dfrac{e^{-6}6^1}{1!})\\\\=1-0.0173512652367\\\\=0.982648734763\approx0.9826$

Hence, the probability that at least two calls are received in a given two-minute period is 0.9826.

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In the given figure lines XY and MN intersectato. If YOP-90° and a: b=2:3, find