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sarah8479
05.05.2020 •
Mathematics
In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of the cross section be x and formed a right triangle with hypotenuse r, as shown below.
The cross-sectional area of the shaded circle is πx2. Using the Pythagorean theorem for the right triangle, we get x2 + b2 = r2. Now solve for x2 and substitute it into the area expression.
What is the result?
π(r2 – b2)
π(r2 + b2)
π(b2 – r2)
2π(b2 + r2)
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Ответ:
it's A
Step-by-step explanation:
Just took the assignment on EDG
Ответ:
hi there! the answer would be,
a. π(r2 – b2)
hope this helps :)
Step-by-step explanation:
i just did the assignment
Ответ: