melaniem50
28.01.2020 •
Mathematics
In triangle abc, a = 2, c = 6, and cos b = . find b.
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Ответ:
Use Law of Cosines, which is ß² = α² + c² - 2αccos(B) where <B is opp. to side ß.
Let α = 2, c = 6 and cos(B) = 1/6, so
ß = √(2² + 6² - 2(2)(6)(1/6))
= √(4 + 36 - 4)
= √36 = 6
Ответ:
$32,525.58
Step-by-step explanation: