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taten1701
20.01.2020 •
Mathematics
In triangle def measurement angle d = 45 degrees meausrement angle e = 63 degrees and ef = 24 inches. what is de to the nearest tenth of a inch?
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Ответ:
DE = 32.8 inches is the answer.
Step-by-step explanation:
It is given that In the given triangle DEF, angle D = 45°, ∠E = 63° and EF = 24 inches.
We have to calculate the length of DE.
From the sine rule of a triangle
As we know sum of all angles of a triangle is 180°
Therefore ∠D + ∠E + ∠F = 180°
45 + 63 + F = 180
F = 180-108 = 72°
Now from the sine rule written above
.029 = .95/DE
DE = 0.95/0.029 = 32.75 ≈ 32.80 inches
Answer will be DE = 32.80 inches
Ответ:
answer:
is 100 times more.
step-by-step explanation: