In triangle try, angle y is a right angle and sin is r=3/5 what are the cosine and the tangent of angle t

I'll TRY to answer this question as best as I can. (No? Bad pun? Ignore it.)
Anyways...
From angle R, we have a sine (opposite/hypotenuse) value of 3/5.
This means that we have a 3/4/5 right triangle.
Now, shifting to angle T (we'll have to visualize all of this), the "opposite" value of 3 from angle R becomes the "adjacent" value of angle T.
So, cosine of angle T is going to be 3/5.
Since we know that the adjacent value of T is 3, and that the hypotenuse is 5, the opposite side from T must be 4.
Tangent is opposite/adjacent, so tangent of angle T is 4/3.

h=1ft

Step-by-step explanation:

The volume of a cone is:

v=πr^h/3

plug in the values (I am assuming not 1/18π but 1/18×π):

1/18π=  π1/3^2h/3

Get rid of the radius:

1/3^2=1/9

Continue:

π/18= πh/3*1/9= πh/18

Remove the denominators:

π=πh

Divide both sides by π :

h=1