Mathematics: In ΔTUV, the measure of ∠V=90°, the measure of ∠T=16°, and VT = 4.9 feet. Find the length of TU to the nearest tenth of a foot.

In ΔTUV, the measure of ∠V=90°, the measure of ∠T=16°,

Lydiac9243

24.01.2022

Given:

Given that TUV is a right triangle.

The measure of ∠T is 16°

The length of VT is 4.9 feet.

We need to determine the length of TU.

Length of TU:

The length of TU can be determined using the trigonometric ratio.

Thus, we have;

$cos \ \theta=\frac{adj}{hyp}$

where $\theta=16^{\circ}$ , adj = TV and hyp = TU

Thus, we get;

$cos \ 16^{\circ}=\frac{4.9}{TU}$

Simplifying, we get;

$TU=\frac{4.9}{cos \ 16^{\circ}}$

$TU=\frac{4.9}{0.9613}$

TU=5.097

Rounding off to the nearest tenth, we get;

TU=5.1

Thus, the length of TU is 5.1 feet.

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jazz9876

14.11.2020

-58185.70868

Step-by-step explanation:

Ello, so basically yh

the way u work this out is by: go on google nd ask this same maths question

and then the anwer will come.

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