Integrate (sqrt((x-1)/x^5)) using substitution (no trig substitution)

√ (( x - 1) / x^5) = 1/√x^4 · √(1 - 1/x )= 1/x² · √( 1 - 1/x )
Substitution:
u = 1 - 1/x
d u = 1/x² dx

A (0,0) is at the origin.
P is at (10, -5).

Let the coordinates of B be (x,y).
Because A,  B, and P are collinear and PB : AB = 2/7, therefore
x = (7/9)*10 = 7.78
y = (7/9)*(-5) = -3.89

The distance between B and the x-axis is 3.89
The distance between B and the y-axis s 7.78

The x-axis is closer to B