Internet and Computer Exercise 1 (From Marketing Research (6th Edition) ,Page 600: Chapter 18, Internet Exercise 1)- Conduct a two-group discriminant analysis on the data given in Tables 18.2 and 18.3 using SPSS (SAS and Minitab not needed). Compare the output and discuss similarities and differences. The comparison is about the similarities and differences in
a) the significance values of the discriminant coefficients,
b) percentage of original grouped cases correctly classified, and
c) percentage of cross-validated grouped cases correctly classified across the three datasets

P = 0.075     P = 7.5%

Step-by-step explanation:

We pretty much look for the probability that the player fails the first attempt and also fails the second attempt.

We know for a fact that the probability that the quarterback fails the first attempt is:

p(1) = 0.5

and we know that the probability that the quarterback fails the second attempt after failing the first is:

p(2/1) = 0.15  

Then the probability of failure of both attempts is:

P(2/1) = p(1 and 2) / p(1)

p(1 and 2) = P(1) * P(1/2)

p(1 and 2) = 0.5 * 0.15

and that is

p(1 and 2) = 0.075

you probably didn't want the nerdy stuff but oh well