carebear147
24.11.2020 •
Mathematics
IQ scores (as measured by the Stanford-Binet intelligence test) in a certain country are normally distributed with a mean of 95 and a standard deviation of 18. Find the approximate number of people in the country (assuming a total population of 323,000,000) with an IQ higher than 126. (Round your answer to the nearest hundred thousand.)
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Ответ:
13,797,339 people
Step-by-step explanation:
Given that μ = 95 and σ = 18
The total number of population is N = 323,000,000
Now, we calculate the probability that IQ is higher than 126
P(X>126) = 1 - P[Z ≤ 126 - 95 / 18]
P(X>126) = 1 - P[Z ≤ 1.72]
P(X>126) = 1 - [ NORMSDIST(1.72)] Using MS Excel
P(X>126) = 1 - 0.957283779
P(X>126) = 0.042716221
Hence, the required probability is 0.042716221
Now, we calculate the approximate number of people in the county with an IQ higher than 126
Number of people = P(X>128) * N
Number of people = 0.042716221 * 323,000,000
Number of people = 13797339.383
Number of people = 13,797,339
Therefore, the approximate number of people in the country with an IQ higher than 126 is 13,797,339 in population
Ответ:
The answer is 7.386363 repeated
Rounded, the answer is 7 miles