Irealy need ! will give brainliest!
of segments cfd and ced, which of the segments has a greater area based on the given information?
circle a: radius = 10m, m∠cad = 90°
circle b: radius = 12m, m∠cbd = 60°

If I am understanding you correctly,  first solve for the whole sector, which you can use this formula. 

Once you find the area of the sector, all you have to do is get the area of the triangle and then subtract the area of the triangle from the sector and that will tell you the area of CFD and CED and let you know which one is greater.

For instance, Lets find A

sector area =  

Now lets get the area of the triangle, which is 

area triangle = 

area triangle =

CED =  sector area - area of triangle =

Now lets find B

sector area =  

Now lets get the area of the triangle, which is 

area triangle = 

area triangle =

CFD = sector area - area of triangle =

So A has the greater area base.

what?

Step-by-step explanation:

Consider diffusion inside an enclosed circular tube. Let its length (circumference) be 2l. Let x denote the arc length parameter where −l ≤ x ≤ l. Then the concentration of the diffusing substance satisfies ut = kuxx for − l ≤ x ≤ l u(−l, t) = u(l, t) and ux (−l, t) = ux (l, t). These are called periodic boundary conditions. (a) Show that the eigenvalues are λ = (nπ/l) 2 for n = 0, 1, 2, 3,... . (b) Show that the concentration is u(x, t) = 1 2 A0 +[infinity] n=1 An cos nπx l + Bn sin nπx l e−n2π2kt/l 2 .