Is (3,-2) the solution to this system of equations? yes or no (circle one) -2x-4y=2 3x+4y=8

(2,−1)

Explanation:

The quickest way is to use elimination

3x+4y=2

                 +

2x−4y=8

−−−−−

5x      =10

⇒   x=2

Now substitute into one of the original eqns.

3×2+4y=2

6+4y=2

4y=−4⇒y=−1

check in other eqn.

2x−4y=8

2×2−(4×−1)=4−−4=4+4=8√

solns (2,−1)

i forgot ill keep looking tho

Step-by-step explanation: