Mathematics: Is x2 + a polynomial? justify your answer.

Is x2 + a polynomial? justify your answer.

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Ashley606hernandez

05.05.2020

Keywords:

average rate of change, parabola, interval, points

For this case we have to find the average rate of change of a parabola in the interval from x = -2 to x = 0 . To do this, we need two points for the parabola pass, and apply the following formula:

$AVR = \frac {f (x_ {2}) - f (x_ {1})} {x_ {2} -x_ {1}}$

We have the following points, taking into account that y = f (x) :

$(x_ {1}, f (x_ {1})) = (- 2, -1)\\(x_ {2}, f (x_ {2})) = (0, -1)$

Substituting:

$AVR = \frac {-1 - (- 1)} {0 - (- 2)}\\AVR = \frac {-1 + 1} {0 + 2}\\AVR = 0$

So, the average rate of change for the given graph is 0 in the given interval

$AVR = 0\ from\ x = -2\ to\ x = 0$

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Is x2 + a polynomial? justify your answer.

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