rileyeddins1010
05.03.2021 •
Mathematics
Isabella is ordering invitations
for her 13th birthday
party. She is choosing between two companies.
Clear Print Invitation charges $2 per invitation.
Invitations by Sue charges $36 plus $.50 per
invitation.
For each company, write an equation that Isabella
could use to calculate the cost of any number of
invitations.
Equation for Clear Print Invitation
Equation for Invitations by Sue
Isabella plans to order 60 invitations, which company
will offer the better price for the 60 invitations?
Solved
Show answers
More tips
- F Food and Cooking Do Aphrodisiacs Really Work? Separating Fact from Fiction...
- C Computers and Internet Log-in: what is it and why do you need it?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
Answers on questions: Mathematics
- M Mathematics All sets in which the number 154 is an element...
- M Mathematics Consider the partial construction of a line parallel to liner through point Q. What would be the final step in the construction? Draw a line through P and S. Draw a line...
- M Mathematics Which of the following is the final step in copying an angle? Place a compass on the vertex of the new angle, and swing an arc similar to the first one you created draw...
- M Mathematics 3 Determine whether the following sets form sub- spaces of R2 for (a)–(e) and subspaces of R2×2 for for (d)–(g) (a){(x1, x2) t : x1 + x2 = 0} (b){(x1, x2) t : x1x2 =...
- M Mathematics Construct a truth table for the logical operator nand....
- M Mathematics Suppose we approximate the value of 1/128 by rounding to 3 decimal places. a) what would be the approximation? b) what is the number of significant digits in the approximation?...
- M Mathematics Determine whether these two statements are logically equivalent by constructing truth tables. -(pa-q) and pvq after you construct truth tables, explain why they are logically...
- M Mathematics Decision science assume more restrictions. the books pass through two departments: graphics and printing, 1. before they can be sold, x requires 3 hours in graphics and...
- M Mathematics Their difference problem 5 (ex 2.20) suppose that you place 1000 points at random in a squarer region measuring one foot by one foot. show that at least seven of them...
- M Mathematics An ellipsoidal coordinate system is similar to spherical coordinates, but stretched in each dimension. consider the half-ellipsoid corresponding to a z 0 hemisphere centered...
Ответ:
Sue: y = 36 + 0.50x
Clear Print: y = 2(60) = $120
Sue: y = 36 + 0.50(60) = $66
Sue offers the better price for 60 invitations
Ответ:
For the first position there are two candidades ( Zack / Paul )
For the second position there is only one candidate i.e. Dave
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4)
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place )
For the fifth place there will be 2 candidates
Finally, for the last place there will be only one candidate left.
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A)
Please mention minor spelling mistakes
For the second question:
Let the no of dotted marbles be 'x' and no of striped marbles be 'y'
then the equation will become as follows
(y+6)/x = 3
and
(x+6)/y = (2/3)
On solving the equations, we will get x = 10 and y = 24
Total balls = 10+24+6 = 40 (option E)
Answer 3 will be ) For the first edge, he can choose 3 paths
For the second edge he can choose 2 paths for each path of its first edge's path
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together
It will be multiplication of all the possibilities of the paths of the three edges differently
i.e. 3 * 2 * 1 = 6