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Mw3spartan17
12.03.2020 •
Mathematics
It costs 20 cents to receive a photo and 30 cents to send a photo from a cellphone. C is the cost of one photo (either sent or received). The probability of receiving a photo is 0.6. The probability sending a photo is 0.4. (a) Find PC(c), the PMF of C. (b) What is E[C], the expected value of C
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Ответ:
(a) PC(C)=![\left \{ {{0.6 \ \ \ \ x=20} \atop 0.4 \ \ \ \ {x=30}} \right. \\\ 0 \ \ \ \ \ \ \ else](/tpl/images/0543/8232/fc49f.png)
(b) E[C] = 24 cents
Step-by-step explanation:
Given:
Cost to receive a photo = 20 cents
Cost to send a photo = 30 cents
Probability of receiving a photo = 0.6
Probability of sending a photo = 0.4
We need to find
(a) PC(c)
(b) E[C]
Solution:
(a)
PC(C)=![\left \{ {{0.6 \ \ \ \ c=20} \atop 0.4 \ \ \ \ {c=30}} \right. \\\ 0 \ \ \ \ \ \ \ else](/tpl/images/0543/8232/febef.png)
(b)
Expected value can be calculated by multiplying probability with cost.
E[C] = Probability × cost
E[C] =![0.6\times20 +0.4 \times 30 = 12 + 12 = 24\ cents](/tpl/images/0543/8232/d348e.png)
Ответ:
answer:
sum Y
Step-by-step explanation: