Jack’s shipping company has to transport boxes of industrial nuts and industrial bolts to its clients. each box of industrial nuts weighs 100 kilograms, and each box of industrial bolts weighs 200 kilograms. the maximum weight the company’s cargo container can hold is 24,000 kilograms. to minimize transportation costs, the company needs to transport a minimum of 160 boxes per cargo container. let x be the number of boxes with industrial nuts, and y be the number of boxes with industrial bolts. which of the following graphs represents the situation with the solution region shaded? graph a graph b graph c graph d cannot be determined from the given information

The correct option is B.

Step-by-step explanation:

Let the boxes of nuts be x and the boxes of bolts by y.

The weight of nut box is 100 kg and the weight of bolt box is 200 kg.The maximum weight the company’s cargo container can hold is 24,000 kilograms.

                            .... (1)

The company needs to transport a minimum of 160 boxes per cargo container.

                            .... (2)

Plot the above inequalities on the coordinate plane.

The related equations are

                       .... (3)

                          .... (4)

The x-intercept of equation 3 is (240,0) and the y-intercept is (0,120).

The x-intercept of equation 4 is (160,0) and the y-intercept is (0,160).

Check the inequality by (0,0).

This statement is true, therefore the shaded region of inequality (1) contains (0,0).

\

This statement is false, therefore the shaded region of inequality (2) does not contains (0,0).

Therefore graph (2) represents the solution and option B is correct.

OK.  So they sold 200 raffle tickets, and Jennie bought 5 of them.
What has to happen now in order for Jennie to win both prizes ?

-- First drawing.  Jennie wins.
   Probability  =  (5 tickets) / (200 possible draws)  =  5/200

   Now there are 199 tickets left in the barrel, and Jennie has 4 .

-- Second drawing.  Jennie wins.
    Probability  =  (4 tickets) / (199 possible draws)  =  4/199 .

The probability of it happening just this way is

                   (5/200) x (4/199)

             =    (5 x 4)  /  (200 x 199)

             =      20      /      39,800

             =            2  /  3,980  =  1 / 1,990 

             =                                0.0005025...  =  0.05 %  (rounded)