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mia3128
10.04.2020 •
Mathematics
Jamal ran 8 kilometers ,sprinted 500 meters and climbed bleachers fr a distance of 1.5 kilometers during track practrice. How meany meters in totle did he traveled dinring prsctrice.
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Ответ:
10 km
Step-by-step explanation:
Running distance = 8 km
Sprinting distance = 0.5
Climbing distance = 1.5
TOTAL = 10 km
Jamal travelled 10 km in total.
Ответ:
1. Mean = 55.8
Median = 23
Mode = None
2. Mean = 2.1
Median = 1.4
Mode 0.5
3. Mean = 4.5
Median = 4.5
Mode = 1,4, 5, 8
4. Mean 68
Median 58
Mode = 0
Step-by-step explanation:
Mean = 17 + 25 + 23 + 200 + 14 / 5 = 279/5 = 55.8
Median= Because its odd you put them in order 17, 14, 23, 25, 200 = 23 because it is the middle number. Mode = None
2. Mean = 0.5 + 1.4 + 3.0 + 7.0 + 0.5 +1.8 + 0.5 = 14.7 = 14.7/7 = 2.1
Median = because it is odd you put them in order 0.5, 0.5, 0.5, 1.4, 1.8, 3.0, 7.0 = 1.4 The mode is 0.5 because it repeats three times
3. Mean = 1 + 8 + 5 + 4 + 1 + 8 + 5 + 4 = 36/8 =4.5
Median = Because its even you divide by the two middle numbers = 1, 1, 4,4, 5, 5 , 8 , 8 = 4+5 = 9/2 = 4.5 Mode = 1, 4, 5, and 8 are the numbers that are repeated most often.
Mean = 0+78+99+58+65+0+47+38+227 = 68 Median, Because there is an odd number you get the odd number from the middle. 0, 0, 38, 47, 58, 65, 78, 99, 227 = 58 Mode = 0 because it repeats more often.
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