Janet, Kay, and Lam are hiking. Lam forgot to bring water. Janet brought 2 gallons of water and Kay brought 1 3/4 gallons of water. The three of them agree to divide all the water equally among them. Lam gives $2 for the water he receives, which Janet and Kay agree to divide fairly between the two of them. How much money should Janet receive?

Janet should receive $1.20

Kay should receive $0.80

Step-by-step explanation:

Janet=2 gallons

Kay=1 3/4 gallons=1.75

Total=2+ 1 3/4

=2+7/4

=8+7/4

=15/4 gallons

They agreed to share it equally

15/4÷3

=15/4×1/3

=15/12=1.25

=5/4 each individual gets 5/4

Janet=2-1.25=0.75

Janet gave up 0.75 gallonsof her water

The percentage is

0.75/1.25×100

=0.6×100

=60%

Kay=1.75-1.25=0.50

Kay gave up 0.50 gallons of her water

The percentage is

0.50/1.25×100

=0.4×100

=40%

Janet gets 60% of $2

60/100×$2

=0.6×$2

=$1.2

Kay gets 40% of $2

=40/100×$2

=0.4×$2

=$0.8

Option B is corrrect

thanks