Mathematics: Javier needs to earn at least an 80 in college algebra only exam scores are used to calculate his grade currently he has scored a 73,71 and 82 this semester with the semester exam counting twice what is the minimum score needed on the semester exam to earn an 80 or

Javier needs to earn at least an 80 in college algebra

Ответ:

kataldaine

15.01.2022

Mathematics

The minimum score needed on the semester exam to earn an 80 by Javier is 87.

Step-by-step explanation:

The scores he has scored in the papers = 73, 71 and 82

Let us assume the score Javier scores in the semester exam = p

The average of the total marks = 80

Now , as semester exam is counted TWICE:

The total of all the marks obtained by Javier = 73+ 71 + 82 + p + p

= 226 + 2p

Now, the average marks of 5 papers

= $\frac{\textrm{Sum of total marks of 5 papers}}{{5}} = \frac{226 + 2p}{5}$

But the average here is given to be 80.

$\implies ( \frac{226 + 2p}{5}) = 80\\\implies 226 + 2p = 400\\\implies 2 p = 400 - 226 = 174\\\implies p =\frac{174}{2} = 87$

or, p = 87

Hence, the minimum score needed on the semester exam to earn an 80 by Javier is 87.

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Ответ:

caitybugking

03.12.2020

Mathematics

$\sqrt{a} =a^{\frac{1}{2}}\\\\ \sqrt[3]{c} =c^{\frac{1}{3}}\\\\ \sqrt[5]{x^4} =x^{\frac{4}{5}}\\\\ \frac{1}{ \sqrt{e} } = e ^{\frac{-1}{2}}\\\\ \frac{1}{ \sqrt[7]{x^2} } =x^{\frac{-2}{7}}\\\\ \sqrt[4]{(16a^4)^5} = 32a^5\\\\ \sqrt[8]{(b^{\frac{3}{5}})^5} = b^{\frac{3}{8}}$

$\sqrt[3]{ \frac{c^{15}}{c^9} } =c^2\\\\ \sqrt[3]{27d^2 \times 27d^{-4}} = 9d^{\frac{-2}{3}}$

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Javier needs to earn at least an 80 in college algebra only exam scores are used to calculate his grade currently he has scored a 73,71 and 82 this semester with the semester exam counting twice what is the minimum score needed on the semester exam to earn an 80 or

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