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heavyhearttim
13.11.2020 •
Mathematics
Jill converted the equation of the line 15 x minus 14 y = negative 2 into slope-intercept form and found the slope and y-intercept of the line as follows.
15 x minus 14 y = negative 2. 15 x minus 4 y minus 15 x = negative 2 minus 15 x. negative 4 y = negative 2 minus 15 x. StartFraction negative 4 y Over negative 4 EndFraction = StartFraction negative 2 minus 15 x Over negative 4 EndFraction. Y = StartFraction negative 2 Over negative 4 EndFraction minus StartFraction 15 x Over negative 4 EndFraction. y = one-half minus StartFraction 15 Over 4 EndFraction x. y = negative StartFraction 15 Over 4 EndFraction x + one-half. slope = negative StartFraction 15 Over 4 EndFraction. y-intercept = one-half.
What was her mistake?
She mixed up the slope and the y-intercept.
She got the sign of the slope wrong.
She got the sign of the y-intercept wrong.
She found the reciprocals of the slope and the y-intercept.
Solved
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Ответ:
she got the sign of the slope wrong
Step-by-step explanation:
Ответ:
a. ∫ xSinx dx
iii. integration by parts
u =x and dv= sinx
b. ∫ x⁴/(1+x³). dx
ii. neither
Long division is an option here before integration is done
c. ∫ x⁴. e^x³. dx
i. substitution
where u = x⁵
d. ∫x⁴ cos(x⁵). dx
i. substitution
where u = x⁵
e. ∫1/√9x+1 .dx
i. substitution
where u = 9x+1