Joe starts 5 feet away from a motion detector. He the walks away from the detector at a rate of 0.5 ft per sec for 4 seconds. He remains still for 2 seconds, and then walks toward the detector at a rate of -2 ft per sec for 3 seconds. How far is Joe from the motion detector when he finishes his walk?

65 degree, 15 degree

Step-by-step explanation:

In triangle GEF,

∠E = ∠G (Given)

Let's say,

∠E = ∠G = x

∠E + ∠G + ∠F = 180 (Angle sum property of Triangle)

=>x + x + ∠F = 180

=>2x + ∠F = 180

=>2x + 50 = 180

=>2x = 180-50

=> 2x =130

=> x = 130/2

=> x = 65

=>∠E = ∠G = 65

=>∠GEF = ∠EGF = 65 Degree

∠EGF + ∠CGF = 180

=>65 + ∠CGF =180

=>∠CGF = 180 - 65

=> ∠CGF = 15