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emmiles2005
10.06.2020 •
Mathematics
John averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. Suppose John's words per minute on a minute on a typing test. Then X~N(58,11)
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Ответ:
The z score when x =72 is:
The mean is 58
This z-score tells you that x= 72 is 1.273 standard deviations to the right of the mearn.
Step-by-step explanation:
Assuming the following info for the question: Suppose John's words per minute on a typing test are normally distributed. Let X -the number of words per minute on a typing test. Then X N(58, 11) If necessary, round to three decimal places.
Provide your answer below rds per minute in a typing test on Sunday. The z score when x =72 is
For this case we know that the variable of interest is modelled with the normal distribution:
And the z score is given by:
And replacing we got:
The mean is 58
This z-score tells you that x= 72 is 1.273 standard deviations to the right of the mearn.
Ответ:
Because
-4-8=-12
-4*-8=32