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vlactawhalm29
18.12.2020 •
Mathematics
Joshua has a bag of marbles. In the bag are 5 white marbles, 3 blue marbles, and 7 green marbles. Peter randomly draws one marble, sets it aside, and then randomly draws another marble. What is the approximate probability of Peter drawing out two green marbles
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Ответ:
1 / 5
Step-by-step explanation:
Given that:
Number of white marbles = 5
Number of blue marbles = 3
Number of green marbles = 7
Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :
Probability = required outcome / Total possible outcomes
Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles
First draw:
P(Green) = 7 / 15
Second draw:
Required outcome = 7 - 1 = 6
Possible outcomes = 15 - 1 = 14
P(green) = 6 / 14
Probability of drawing out two green marbles :
(7/15 * 6/14) = 42 / 210 = 1 / 5
Ответ: