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emmadivaburnsox7ae9
14.10.2019 •
Mathematics
Joyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. she has made an error in one of the steps below. find the step where joyce went wrong. (1 point)
step 1: x equals negative 8 plus or minus the square root of the quantity eight squared minus four times one times seven, end quantity, all over two times one.
step 2: x equals negative 8 plus or minus the square root of sixty-four minus twenty-eight all over two times one.
step 3: x equals negative 8 plus or minus the square root of thirty-six all over two times one.
step 4: x equals negative 8 plus or minus six all over two.
step 1
step 2
step 3
step 4
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Ответ:
The parameters a, b and c represent the coefficients of the standard form of the quadratic equation: y = ax^2 + bx + c. Thus, for the equation y = x2 − 8x + 7,
a = 1
b = -8
c = 7
The mistake Joyce made was in Step 1. Because Step 1 is wrong, the rest of the equation is wrong consequently. The mistake was made by Joyce when she assigned b = 8. She forgot to include the negative sign of -8x.
Ответ:
umm ok?
Step-by-step explanation: