Kailee paid $14.84 for stamps. the number of - id1484494162187, mirzakasumovic8926

Ответ:

Jackiecroce12

12.01.2022

Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

Step-by-step explanation:

Given:

Total Money paid for stamps = $14.84

Let the number of 49-cents stamps be x.

Also Let the number of 21-cents stamps be y.

Now Total Money paid is equal to sum of number of 49-cents stamps and number of 21-cents stamps.

100 cents = 1$

So 49 cents = $0.49

and 21 cents = $0.21

Hence equation be framed as;

$0.49x+0.21y =14.84 \ \ \ \ equation \ 1$

Also Given:

number of .49-cents stamps was four less then three times the number of 21-cent stamps.

hence we can say that;

$x=3y-4\ \ \ \ equation \ 2$

Now Substituting the value of equation 2 in equation 1 we get;

$0.49(3y-4)+0.21y=14.84\\1.47y- 1.96+0.21y=14.84\\1.68y=14.84+1.96\\1.68y = 16.8\\y=\frac{16.8}{1.68}=10$

Now substituting the value of y in equation 2 we get;

$x=3y-4\\x=3\times10-4\\x=30-4\\x=26\\$

Hence Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

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