Kyle has 22 more cards than 3 times the number of cards that Stan owns. Together, they own less than 58 cards. How many cards are in stand collection? A- Stan owns 9 cards or less
B- Stan owns 9 cards or more
C- Stan owns less than 9 cards
D- Stan owns more than 9 cards

i think the answer is c

Step-by-step explanation:

22x3=66 66-58=8

You forgot to say what the question actually is ! 

But  I've seen this problem before, in the last few days, here on 
I think the problem has three parts:  1). Solve the equation for 'a'; 
2). Solve it for 'b'; and 3). Solve it for 'c'.

I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.

1).  Solve the equation for 'a'.  That means you have to wind up with something
that says      a = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  (b/c +1)  from each side:      D - b/c - 1  =  a/c

Multiply each side by 'c' :                  Dc - b - c  =  a


2).  Solve the equation for 'b'.  That means you have to wind up with something
that says      b = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  (a/c +1)  from each side:      D - a/c - 1  =  b/c

Multiply each side by 'c' :                  Dc - a - c  =  b


3).  Solve the equation for 'c'.  That means you have to wind up with
something that says      c = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions:      D = a/c + b/c + c/c

But  c/c =1 ,  so the equation says      D = a/c + b/c + 1

Subtract  1  from each side:          D - 1 = a/c + b/c

The two fractions on the right can be added/combined:    D - 1 = (a + b) / c

Multiply each side by  'c' :          c(D - 1) = (a + b)

Divide each side by  (D - 1) :      c  =  (a + b) / (D - 1)