Last year, a school had 632 students. This year the school has 670 students. Find the percent of increase in the number of students.

I don't know

Step-by-step explanation:

but what I do know is to not increase your days is bad

I'm pretty sure this is the answer

Step-by-step explanation: k is increased by 20% which means new k will be 1.2k. Similarly new x will be 1.2x and

new y will be 1.2y.

So, new T will be 1.2x×1.2x

1.2y which is equal to 1.2kx/y. Therefore, now we have

original T =kx/y

and new T =12.kx/y

increase in T is given by 1.2kx/y −kx/y which is equal to 0.2kx/y.

original     increase

kx/y         0.2kx/y

100 ?

?= 0.2kx/y ×100/kx/y

which is equal to 20% (cancel kx/y)