Let an = 1 4n − 1 for n = 1, 2, 3, . write out the the first three terms of the following sequences. (a) bn = an + 1 b1 = 4/3 b2 = b3 = (b) cn = an + 3 c1 = c2 = c3 = (c) dn = an2 d1 = d2 = d3 = (d) en = 2an − an + 1 e1 = e2 = e3 =

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