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dianacastro8298
20.01.2021 •
Mathematics
Let f be a differentiable function defined by f(x) = 3x + 2e −3x , and let g be a differentiable function with derivative given by g′(x) = 1 x + 4. It is known that lim g(x) = [infinity].
x→[infinity]
The value of lim f(x) g(X) is:
x→[infinity]
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Ответ:
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Ответ:
they are
x,x+2,x+4,x+6
they sum to -92
x+x+2+x+4+x+6=-92
4x+12=-92
minus 12 both sides
4x=-104
divide both sides by 4
x=-26
x+2=-24
x+4=-22
x+6=-20
they are -26,-24,-22,-20