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jackchris2732
29.06.2019 •
Mathematics
Let f be the function defined as follows: f of x equals the piece-wise function absolute value of the quantity x minus one end quantity plus two for x is less than one, a x squared plus b x for one is less than or equal to x is less than two, and five x minus ten for x is greater than or equal to two where a and b are constants [x-1]+2 x< 1 ax^2+bx 1=x< 2 5x-10 x> /=2 if a = 2 and b = 3, is f continuous at x = 1? justify your answer. find a relationship between a and b for which f is continuous at x = 1. hint: a relationship between a and b just means an equation in a and b. find a relationship between a and b so that f is continuous at x = 2. use your equations from parts (ii) and (iii) to find the values of a and b so that f is continuous at both x = 1 and also at x = 2? graph the piece function using the values of a and b that you have found. you may graph by hand or use your calculator to graph and copy and paste into the document.
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Ответ:
With
defined by
in order for it to be continuous at
, we require
(i) If
and
, then
and
The limits don't match, so
is not continuous at
under these conditions.
(ii) To establish continuity at
, we'd need the limit as
from the right to be equal to the limit from the left, or
(iii) We have
and
For
to be continuous at
, then, we'd need to have
(iv) Taking both requirements from parts (ii) and (iii), we solve for
:
I've attached a plot that confirms this is correct.
Ответ: