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vallhernandez13
05.11.2019 •
Mathematics
Let f(x)=20/1+9e^3x .
what are the asymptotes of the graph of f(x) ?
select each correct answer.
y = 3
y = 0
y = 9
y = 20
Solved
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Ответ:
y = 0 and y = 20
Step-by-step explanation:
The given function is![\left(\frac{20}{\left(1+9e^{3x}\right)}\right)](/tpl/images/0359/7216/69499.png)
There is no vertical asymptotes because the denominator will never be zero.
Horizontal asymptotes are given by
Take the constant 20 out of the limit
Now, we can further simplify as follows
Similarly, the second horizontal asymptote is
We can simplify this limit as we did the previous one
Hence, asymptotes of the graph of f(x) are
y = 0 and y = 20
Ответ:
do you have a picture
Step-by-step explanation: