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ryleigh8211
28.05.2020 •
Mathematics
Let f(x)=3x^2-8 and let g(x)=4x+1. Find the given value f[g(-1)]
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Ответ:
19
Step-by-step explanation:
given:
f(x)=3x²-8
g(x)=4x+1
g(-1) = 4(-1)+1
g(-1) = -4 + 1
g(-1) = -3
hence
f[g(-1)]
= f(-3)
= 3(-3)²-8
= 3(9) - 8
= 19
Ответ:
= [(6×4)+3/4] + [(4×3)+2/3]
= 27/4 +14/3
Common multiple of 4 and 3 = 12
(27×3)/(4×3) + (14×4)/(3×4)
= 81/12 + 64/12
= 145/12 = 12 1/12