Let f(x) = x2 + 6 and g(x)= x+8/x . find ( g o f)(­ -7)

(g o f)(x)=g(f(x))
so

(g o f)(-7)=g(f(-7))=
g((-7)^2+6)=
g(49+6)=
g(55)=
55+8/55=
55 ad 8/55

(g o f)(-7)=55 and 8/55
(if you meant g(x)=(x+8)/x, then the result is 63/55 or 1 and 8/55)

Note! Every triangle must add up to 360°

1. x =
(×+29°) + (x+19°) + 84° = 360°
x + x + 29° + 19° + 84°= 360°
2x + 48° + 84°= 360°
2x + 132° = 360°
2x = 228°
x = 114°

m(angle)A =
(x+29°)
(114°+29°)=143°

m(angle)B=
(x+19°)
(114°+19°)=133°

3. is a bit different

(3x+6)° = (8x+3)°+130°
-5x+6° = 3° + 130°
-5x = 133° - 6°
-5x = 127°
x = -25.4°

m(angle)A=
(3x+6)°
3×(-25.4)+6= -70.2°

m(angle)DBE=
(8x+3)°=
8(-25.4)+3= -200.2°

I only did 1. and 3. for examples now, but if you need help with anymore just ask!