Mathematics: Let x be a random variable that represents the ph of arterial plasma (i.e., acidity of the blood). for healthy adults, the mean of the x distribution is μ = 7.4.† a new drug for arthritis has been developed. however, it is thought that this drug may change blood ph. a random sample of 31 patients with arthritis took the drug for 3 months. blood tests showed that x = 8.6 with sample standard deviation s = 2.9. use a 5% level of significance to test the claim that the drug has changed (either way)

Let x be a random variable that represents the

Hfruit

10.01.2022

2.304

Step-by-step explanation:

Given that x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood).

$n=31\\\bar x = 8.6\\s=2.9\\se = \frac{2.9}{\sqrt{31} } \\=0.5209$

$H_0: \bar x =7.4\\H_a: \bar x \neq 7.4$

(Two tailed test at 5% level)

Mean difference = 8.6-7.4=1.2

b) Here we can use only t test since population std deviation is not known.

df = n-1 = 30

Test statistic t = mean diff/std error = 2.304

p value = 0.028

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