alexisbcatlett14
18.10.2020 •
Mathematics
Letica simplified an expression her work is shown below step one
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Ответ:
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = pi*r2*H
V of cylinder = pi*(4/2)^2*(6)
V of cylinder = 75.4 ft3
V of cone = pi*r2*H/3
V of cone = pi*(4/2)^2*(4.5/3)
V of cone = 18.85ft3
Total volume = 94.25ft3