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2643050
10.03.2020 •
Mathematics
Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 43.8° with the normal to the surface, while in the slab it makes an angle of 19.3° with the normal. What is the index of refraction of the transparent material?
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Ответ:
Index of refraction of transparent is 1.48
Step-by-step explanation:
Snell's law states that;
n1(sinθ1) = n2(sinθ2)
Where;
n1 and n2 represent the indices of refraction for the two media, and θ1 and θ2 are the angles of incidence and refraction that the ray R makes with the normal.
In this question;
n1 = 1;
θ1 = 43.8°
θ2 = 19.3°
n2 is unknown.
Thus using Snell's law, we have;
1 x sin 43.8 = n2 x sin 19.3
n2 = (sin 43.8)/sin 19.3
n2 = 1.48
Ответ: