kaylallangari2145
27.07.2020 •
Mathematics
find the sum of even numbers between 1001 and 10,000 (Arithmetic progressions) DO STEP BY STEP PLEASE
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Ответ:
Step-by-step explanation:
arithmetic progression
even numbers between 1001 and 10000
1002,1004,9998
Tn=a+(n-1)d
Tn = 9998 last term in the progression of even numbers
a = 1002 first term
d = 2 distance
9998=1002+(n-1)(2)
8996=2n-2
8998=2n
n = 4499 the number of terms
sum = n/2 (a+Tn) = 4499/2(1002+9998)
= (4499/2)(11000) = 24744500
Logic:
notice what happens when you add the first and last terms
1002+9998=11000
1004+9996=11000
Ответ:
The relationship between <7 and <8 can be said to be vertically opposite angles. They are equal to one another and formed by the intersection of two straight lines. i.e. the intersection of lines C and D.
The special angles created by the intersection of lines C and D can be used to solve for y because they all are inter woven and connected to one another either supplemtarily or by being vertically opposite angles.
5y - 29 = 3y + 19( vertically opposite angles)
5y - 3y = 19 + 29
2y = 48
y = 48/2
= 24.
<7 = <8
<7 + 5y - 29 = 180°( angles on a straight line)
<7 = 180° + 29 - (5 × 24)
= 209 - 120
<7 = 89°
<8 = 89° (vertically opposite angles)