Line cd passes through points c(3, –5) and d(6, 0). what is the equation of line cd in standard form?

C= (3, -5) aND D= (6, 0)
y-y1 = m (x -x1). 
i.e. if x1, y1 = 3, -5 and x2, y2 = 6,0 then#
y- (-5) = m(x - 3), so all we are missing is the slope:

Y2 -y1
  = m (the slope)
x2 -x1
0-(-5)
= 0+5 /3 = 5/3
6 - 3 

therefore equation of line is y+5 = 5/3 (x - 3) 

Hello!

To solve, we need to first find the slope of the line. We can do this by using the formula y2-y1/x2-x1. We can switch the ones and twos and the slope will be the same. We will have (3,-5) be (x1,y1) and have (6,0) be (x2,y2). Now we will plug it into the formula.

0+5/6-3
5/3

Our slope is 5/3, and now we will put it into the slope intercept equation.

y=5/3x+b

Now we will select a point on our line (6,0) and plug it into the equation and solve for b.

0=5/3(6)+b
0=10+b
0-b=10
b=-10

Now we can put it in slope intercept form.

y=5/3x-10

Just to check, we will plug in 3 and see if it equals -5.

y=5/3(3)-10
y=5-10
y=-5

The equation for the line CD is y=5/3x-10

I hope this helps!

First one: (3).3+ ({8.2} - {4.6})
9+ (16- 24)
9 + (-8)
9-8
1
Second one: 8+6.3.2
8+ 36
44
Third one: 3.8+ 6.2.3
24+ 36
60
Four one: (2.5)2+ 4.3.2-5
10.2+ 24-5
20+ 19
39
I hope this helps.