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jr928718
03.03.2020 •
Mathematics
Line P R and Line Q S are diameters of circle T. What is the measure of Arc S R?
50°
80°
100°
120°
Solved
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Ответ:
Option C:
m(arc SR) = 100°
Solution:
∠PQT = 40°
QT and PT are radii of circle.
QT = PT
ΔPQT is an isosceles triangle.
⇒ ∠PQT = ∠QPT = 40° – – – (1)
Similarly, ΔRST is an isosceles triangle.
⇒ RST = ∠SRT – – – (2)
In ΔPQT and ΔRST,
PT ≅ TR (Radii of circle)
ST ≅ TQ (Radii of circle)
∠PQT ≅ ∠STR (by vertical theorem)
Hence ΔPQT ≅ ΔRST by SAS congruence theorem.
By corresponding parts of congruence triangles are congruent.
∠PQT = ∠RST = 40° (by (1))
∠QPT = ∠SRT = 40° (by (2))
In ΔSTR, sum of all the angles = 180°
40° + 40° + m∠PTQ = 180°
m∠STR = 180° – 80°
m∠STR = 100°
The measure of a central angle and the arc it intercepts are equal in measure.
m∠STR = m(arc SR)
m(arc SR) = 100°
Hence option C is the correct answer.
Ответ:
We first calculate Pablo's height .
4 = 100%
x = 1% (Where x is 1% of Sandra's height.)
cross multiplying the equation, we get:
100x = 4 → x = 4/100 → x = 0.04
If 1% = 0.04, then 10% will be 0.04 × 10 = 0.4
Pablo's height is 4 + 0.4 = 4.4 feet.
Now we repeat the above steps to get Michal's height from Pablo's height
4.4 = 100%
x = 1% so:
100x = 4.4 → x = 4.4/ 100 → x = 0.044
If 1% = 0.044, then 8% will be 0.044 × 8 = 0.35
Michael's height is 4.4 + 0.35 = 4.75 feet.