Dweath50
31.10.2020 •
Mathematics
Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x – 11. Line w is parallel to line v and passes through point (–6, 10). Which is the equation of line w in slope-intercept form?
A. y = 34x + 2
B. y = –34x + 2
C. y = 43x + 2
D. y = –43x + 2
A B C OR D WHICH ONE
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Ответ:
y = (1/34)x + 346/34
Step-by-step explanation:
We are told that; Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x – 11
Now, for a line to be perpendicular to another, it means the slope of one will be the negative reciprocal of the other.
Intercept of y = 34x – 11 will be; m = 34
Thus, slope of v is; -1/34
Now, Line w is parallel to line v and passes through point (–6, 10).
Since the slope of v = -1/34, it means the slope of w will be -1/34 because parallel lines have the same slope.
Thus, using slope intercept form, the equation of line w is;
y - 10 = (-1/34)(x - (-6))
y - 10 = x/34 + 6/34
Multiply through by 34 to get;
34y - 340 = x + 6
34y = x + 346
y = (1/34)x + 346/34
Ответ:
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Step-by-step explanation:
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