Cheyenneross366
07.02.2021 •
Mathematics
Lola's hair today is 24" long. It grows 1.5" per month. She is a pretty tall girl for her age, about 60" right now! Her brother has long hair too. His hair is about 12" long. What does the y stand for?
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Ответ:
If I'm correct, you're asking which variable is the dependent variable y from the question
Answer and explanation:
The equation can be modelled:
y= 1.5x
Where y is the current length of the hair
x is the number of months of hair growth
We can see from the equation therefore that y is a dependent variable that depends on x the independent variable, the number of months, to get a value. In other words given that her hair grows at a constant rate of 1.5 inches per month, her hair length is based on number of months x of growth in inches of hair.
Ответ:
There is a 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
For this problem, we have that:
Based on the study results, we can assume the population mean and standard deviation for the GPA of nontraditional students is and .
We have a sample of 100 students, so we need to find the standard deviation of the sample, to use in the place of in the z score formula.
.
What is the probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65?
This is 1 subtracted by the pvalue of Z when . So
A zscore of 3 has a pvalue of 0.9987.
So, there is a 1-0.9987 = 0.0013 = 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.