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montgomerykarloxc24x
23.11.2021 •
Mathematics
Một công ty bảo hiểm bảo hiểm cho một số lượng lớn người lái xe. Gọi X là biến ngẫu nhiên đại diện cho tổn thất của công ty theo bảo hiểm va chạm và để Y đại diện cho tổn thất của công ty theo bảo hiểm trách nhiệm. X và Y có hàm mật độ khớp. Tính xác suất để tổng số lỗ của công ty ít nhất là 1.
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Ответ:
M^oT
Step-by-step explanation:
ba`o ty X va`Y co`la` : aa tr yyy eeka
Ответ:
About. cm3. 227 is actually 22 over 7.
Step-by-step explanation: